Re: how to load in a build in driver whose index is greater 10 in Windows CE

Hi, Steve, thank you for your reply.

I know I can open it with the $device mount point: "\$device\VCA12".
But I likt this VCA12 as a build in driver, which will be load when the
sytem boots up. I already have VCA0 to VCA9. All of them have a
registry key like this:
[HKEY_LOCAL_MACHINE\Drivers\BuiltIn\Sample]
"Prefix"="VCA"
"Dll"="sample.dll"
"DeviceArrayIndex"=dword:12
"Index"=dword:0
"Order"=dword:30

the question is how to create a registry key for the VCA12, so it can
load in at the boot time.

thanks,

Mike.
Steve Schrock [MS] wrote:
Why is VCA_Init failing?

If it is failing due to a device naming issue, here is the answer. The
prefix-index-colon name is limited to 10 instances (0-9). If you are using
CE 5.0 or greater, you can actually use an index greater than 9. However
instead of opening "VCA12:", you will need to open the driver instance from
the $device mount point: "\$device\VCA12"

Take a look at the "Device File Names" topic in PB Help or MSDN for more
information about this.

--
Steve Schrock
Windows Devices Core BSPs

This posting is provided "AS IS" with no warranties, and confers no rights.

<suqian99@xxxxxxxxxxx> wrote in message
news:1167238862.302385.148420@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Hi, All.

I want to load in a WinCE driver, its index is 12. How to do it?

My registry file is like this:

[HKEY_LOCAL_MACHINE\Drivers\BuiltIn\Sample]
"Prefix"="VCA"
"Dll"="sample.dll"
"DeviceArrayIndex"=dword:12
"Index"=dword:12
"Order"=dword:30

But i failed at the VCA_Init function.

any trick to do this?

thanks,

Mike.


.

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