Re: 2 large hard drive questions

thank you Jonny and David. That definitely clears up the 232.88 GB for me.

However, on the cluster issue, I was wondering what effect cluster size
would have on these big drives. I did install my OS on its own partition,
about 40GB and then formated the rest of the drive on another partition
using disk manager. Thats when I thought about whether or not I should use
the default cluster size, as I usually do, or not? It didn't matter much in
the past with smaller drives but I was thinking that in the same way the
manufacturers use of 1000 instead of 1024 is *much* more apparent now with
the *big* drives that this too (cluster size), may be much more significant
now? maybe using a smaller size gains you significantly more usable space
now? If I remember correctly the smallest unit of storage on the formated
disk is equal to the cluster size, which is a component of file system,
rather than physical hard drive. So if for example you have a 16K cluster
size and you save a 17K file to the partition, it actually takes up 32K of
space.

If my memory is correct, I think I just answered my own question. I would
think smaller cluster size *would* have a much bigger impact now, in
general. It does depend on the types/sizes of files being saved on the
partition.

Am I remembering correctly? what do ya think?

"Jonny" <spamyourself@xxxxxxxxxxxxx> wrote in message
news:eUOjnMY3GHA.4924@xxxxxxxxxxxxxxxxxxxxxxx
"djc" <noone@xxxxxxxxxxx> wrote in message
news:e%23vqWrX3GHA.1588@xxxxxxxxxxxxxxxxxxxxxxx
I just installed a 250GB drive (WD WD2500JB). No problems with BIOS or OS
(xp sp2) recognizing and using the drive, supports 48bit LBA.

However,

1) I noticed that Disk Manager in Windows XP SP2 reports the disk as
232.88 GB? I know that the 'marketing' number on the box of the drives is
not exact and when you do the actual math there are differences between
the 'marketing' number and the 'real' number (largely due to
manufacturers using 1000 instead of the proper 1024 bytes = 1 KB). I
can't think of how to work this out at the moment to see if that is all
my descrepency is, or if there is something else wrong here. I'm used to
working with 20-40 GB drives where these differences did not amount to
much so I know when going to such a large drive they will be compounded.
Is my 232.88 GB correct? and how do I do that math?


232.885591685771942138671875 GB is the actual number. WD refers to MB as
1,000,000 bytes and states the formatted capacity of this specific hard
drive as 250,059 MB.
Another words multiply 250,059 times a million, or 250,059,000,000 gives
the capacity in bits. Divide this by 1024, 3 times, gives you the term in
actual GBs used by the PC.

2) What about the 'allocation unit size' (If I remember correctly this is
the same as the 'cluster' size, correct me if I'm wrong please) when
formating a partition on the drive? I have always left this at the
default value for NTFS partitions. Now that I'm dealing with such a large
drive does this setting become more important? how significant is it?
what should I set it to?

Yep, cluster size. If partitioning with XP's disk manager or XP install
setup CD, just leave it alone when done. It will format it automatically.

If you want a smaller cluster size, make a more suitable size partition
for XP for both the same identical partition for boot and system. Mine is
26GB as an example. Use the remainder of the space for another partition
that may use predominantly large files of your own device.
--
Jonny



.

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