Re: Two XPE partitions in one hard disk.



So if I understand what you are trying to do:

You want to be able to Boot with minlogon to run the actual program that
you're designing, and then be able to reboot with a WinLogon configuration
to run administration and such activities on the same system?

If I have this correct, yes you can do this, and Yes you would need 2
Licenses. if you are shipping 2 different configured images, then you have
to have 2 Seperate Licenses. if you were shipping an image, and then have a
recovery image, you would be OK, but you could not boot to that recovery
image.

This is one way to tackle what you are doing, but I would say that if
you are needing to manage your system and optimize boot time, I would look
at tuning your device with a custom shell, and maybe have some security
features built into your app, that can call windows API's for management.
This will save you time, and definately a lot of configuration headaches. I
personally have seen with WinLogon Configurations boot times in the ~10-15
Second range. Also maybe explore full WinLogon, with something like HORM, so
that you can have an "instant on" feel to the device.

HTH,
JC

--
John Coyne
eMVP
Windows Embedded Black Belt
Arrow Electronics, OCS division



When replying directly to this message remove the NOSPAM_ from the address
"joseph" <joseph@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:E25C1244-1E73-487C-B659-D6BD7AF7ED7C@xxxxxxxxxxxxxxxx
> Hi All,
>
> I wonder does anyone ever experience of create two XPE images and put in
> two
> partitions in one hard disk? I am thinking of creating two XPE images
> (one
> with WinLogon, and one with MinLogon) and implement to two different
> partitions in one hard disk. One partition(MinLogon) can run the main
> program and cut down the boot time. The other(WinLogon) can have the
> administration privilege change the system. Is this a wise deploy? Or,
> there is a better way to do the request I need? If I do this, does it
> mean I
> will need two licienses for one device?
>
> Thanks in advance.
>
> Joseph.


.



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