"A duplicate name exists on the network"
- From: "RaymondSBaxterIII" <RaymondSBaxterIII@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Thu, 5 May 2005 16:30:01 -0700
Upon boot up, a Windows-System Error appears stating "A duplicate name exists
on the network". I appears that the duplicate name is actually my server
workstation. Windows Explorer lists two sets of identical My Computer and My
Network Places under a single Desktop. It appears that my computer has set up
a mirror image of itself both of which appear when setting up the Network
Connections.
The workstation name is different than the workgroup name which is just
WORKGROUP. Just a little background: I have a dual processor (Supermicro)
PIII 1.26MHz motherboard with an Intel onboard 10/100 LAN chipset adapter
(connected to Cox Cable ISP with dynamic IP addressing) and an Intel
EtherExpress Pro/100 PCS LAN Adaptec (connected to NAS IDSL with five static
IP addresses). The cable modem is connected to a Netgear Super 108 Wireless
router with both wireline and wireless connection to desktops. The ISDL modem
is connected to a Linksys 10/100 Hub. My server/workstation is connected to
both the router and the hub. Other connections to the hub include an HP
printer, Intel Netport Express print server, another workstation and a laptop
all with assigned static IP addresses. Everything worked fine until I
disconnected the server/workstation from the hub and/or router as I was
attempting to rearrange the jumper cables. Upon reconnecting the jumpers a
message appeared that the computer had found a new network. I performed a
warm reboot since I was unable to escape out of that message. Now I am unable
to connect to the cable service, cannot locate the print server and must
manually re-establish the connection to the other computers. The duplicate
network only appears upon boot up when both LAN connections are plugged into
their respective LAN adapters. I am hoping to be able to correct the problem
without reinstalling the operating system.
How do I remove this second/duplicate name/image?
.
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