Re: renaming files in directory

Royce wrote:

phil when i try it this is what i get... i have tried messing around with this for while, but i cant seem to figure out where my problem is. thanks for the help


Your problem is that your file names contain spaces and parentheses.

:-)

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C:\>for %a in (c:\new\*.txt) do @(set /a x+=1&echo ren %a !x!%~xa)
35ren c:\new\New Text Document (2).txt !x!.txt
36ren c:\new\New Text Document (3).txt !x!.txt
37ren c:\new\New Text Document (4).txt !x!.txt
38ren c:\new\New Text Document.txt !x!.txt

C:\>for %a in (c:\new\*.txt) do @(set /a x+=1& ren %a !x!%~xa)
39The syntax of the command is incorrect.
40The syntax of the command is incorrect.
41The syntax of the command is incorrect.
42The syntax of the command is incorrect.
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"Phil Robyn [MVP]" wrote:


Royce wrote:

need help creating a batch file (or a single line command) that renames all the files in the directory to numbers from 1 to however many files are in the directory. they will all have the same extension... im sure there is a post in this group somewhere i just couldnt find it. thanks for any help. 

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<Win2000> c:\cmd>for %a in (d:\junkdir\m*.txt) do @(set /a x+=1&echo ren %a !x!%~xa)
1ren d:\junkdir\MSGBOX1.TXT 1.TXT
2ren d:\junkdir\MVSPKG01.TXT 2.TXT
3ren d:\junkdir\MVSPKG02.TXT 3.TXT
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If this appears to do what you intend, remove the word 'echo' to actually do the renaming.
If you try it more than once from the CMD prompt, before the second or subsequent attempts,
issue the command 'set /a x = 0' to reset the counter 'x' to zero; otherwise, it will
continue counting up from the previous value.

--
Phil Robyn
Univ. of California, Berkeley

u n z i p   m y   a d d r e s s   t o   s e n d   e - m a i l



--
Phil Robyn
Univ. of California, Berkeley

u n z i p   m y   a d d r e s s   t o   s e n d   e - m a i l
.

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