Re: renaming files in directory

phil when i try it this is what i get... i have tried messing around with
this for while, but i cant seem to figure out where my problem is. thanks for
the help

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C:\>for %a in (c:\new\*.txt) do @(set /a x+=1&echo ren %a !x!%~xa)
35ren c:\new\New Text Document (2).txt !x!.txt
36ren c:\new\New Text Document (3).txt !x!.txt
37ren c:\new\New Text Document (4).txt !x!.txt
38ren c:\new\New Text Document.txt !x!.txt

C:\>for %a in (c:\new\*.txt) do @(set /a x+=1& ren %a !x!%~xa)
39The syntax of the command is incorrect.
40The syntax of the command is incorrect.
41The syntax of the command is incorrect.
42The syntax of the command is incorrect.
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"Phil Robyn [MVP]" wrote:

> Royce wrote:
> > need help creating a batch file (or a single line command) that renames all
> > the files in the directory to numbers from 1 to however many files are in the
> > directory. they will all have the same extension... im sure there is a post
> > in this group somewhere i just couldnt find it. thanks for any help.
>
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> <Win2000> c:\cmd>for %a in (d:\junkdir\m*.txt) do @(set /a x+=1&echo ren %a !x!%~xa)
> 1ren d:\junkdir\MSGBOX1.TXT 1.TXT
> 2ren d:\junkdir\MVSPKG01.TXT 2.TXT
> 3ren d:\junkdir\MVSPKG02.TXT 3.TXT
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>
> If this appears to do what you intend, remove the word 'echo' to actually do the renaming.
> If you try it more than once from the CMD prompt, before the second or subsequent attempts,
> issue the command 'set /a x = 0' to reset the counter 'x' to zero; otherwise, it will
> continue counting up from the previous value.
>
> --
> Phil Robyn
> Univ. of California, Berkeley
>
> u n z i p m y a d d r e s s t o s e n d e - m a i l
>
.

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