Re: This calculation is just wrong / computer can't count!

"David Wilkinson" <no-reply@xxxxxxxxxxxx> wrote in message
news:uObZQmmCIHA.2324@xxxxxxxxxxxxxxxxxxxxxxx
GT wrote:
"Joseph M. Newcomer" <newcomer@xxxxxxxxxxxx> wrote in message
news:7i4lg3h43bkuvlcmu84d74ivv2avm3pdjn@xxxxxxxxxx
Being a FORTRAN programmer is clearly to your advantage. When we
learned FORTRAN (which
was also my first language) these things were carefully explained to us.
We did not have
the same delusional expectations as the OP because we knew better.

Apparently he is incapable of learning anything. We've tried. He just
won't give up his
delusional system.

... which the rest of the world calls mathematics. You might have been
brainwashed by some ancient Fortran 'lessons', but everyone else in the
world knows that if you express 1/3 1 as a decimal you get a recursive
number and the final digit is always a 3 - NEVER a 7. If your brainwashed
view of the world allows you to accept a 7 as the last digit, then your
fundamental grasp of mathematics has been tainted and you can never rely
on any of your calculations ever again! A 7 as the last digit is WRONG.
Plain and simple - it is WRONG.

GT:

IEEE floating point arithmetic is not wrong; it is just different from the
way you would like it to be.

Yes we have covered this. What the question asked for was help on how to get
my code to conform with the mathematics I am trying to do.


.

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