template typedef

Hi all,

suppose I have a template class like:

template <typename T>
struct X
{
T value;
};

If I need a shared_ptr to this class I declare it like:

std::tr1::shared_ptr<X<char>> XcharPtr;

Is there a way to typedef the first part, so I can do something like:

typedXptr<char> XcharPtr;

I can do it with #defines but there must be a better way...

Thank you

--
Alessandro .

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