Re: partial specialization

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Jack Hanebach wrote:
Victor Bazarov wrote:

template<>
struct A<double, int>
{
void foo() {}
};

and

template<>
void A<double, int>::foo() {}

(other than syntax, of course)?

The former is specialisation, the latter is a definition.

The former is specialization of A _and_ a definition of A::foo,
specializezed for double and int, the later is a definition of A::foo
specialized for double and int (and implicit specialization of A),
yes. Yet the effect of both is exactly the same...

No, it's not. It depends on the contents of struct A<T,U> definition,
which is _changed_ in the former case to a new definition and _used_
(with all relevant parts) to instantiate A<double,int> in the latter
case.

V
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