Re: Can pre-innitialized array be changed?

Hi Victor,

I never said that I am using C, I said, that I am reviewing some C stuff,
since I am looking at some code fragments form a C book. I must of created a
CPP file when I created a new project so I can try these C samples. I think I
chose "Win32ConsoleProject" and then "CPP file". I am not sure though!

So, I don't know.... according to you, If I am to try some C stuff, where I
am sopposed to try it then?

Oh yeah! hmmmm , The string class... I would have to review that.

Victor... Tell me something. I have started all this C programming last
summer. I did read a book in C++ and it was very interesting and enjoyed it.
But, Since September I started reading Petzold's book to understand Win32. I
explained to one of my freinds whichg is a Guru in this stuff...(He was also
certified for newsgroups) that I was reviewing linked lists and string
classes and templates. He nearly yanked the book away from me! telling me
that if I am to program in VC++, that I wouldn't need all that?

I found it strange, because compared to me, he is a genius in
C/C++/VC++/Delphi, so at first I didn't know what to do... But I read up on
the stuff anyways. I don't know if I did good or not, but I did put alot of
time with classes, array of pointers to classes and so forth, (I fully
understood linked lists but didn't really practice much with them since I was
told that it wasn't neccessary in VC++)

Can you share your sincere opinion with me! Is it true that most of the
programming in VC++ doesn't really require you to know linked lists, and
string class etc.. ?

--
Best regards
Robert


"Victor Bazarov" wrote:

Robby wrote:
I am reviewing some array stuff in 'C' and I would like to understand
something. The code fragment below displays the words innitialized in the
words array.

===============================================
char words[][2][10] =
{
"We", "Are",
"All", "Human"
};

printf("All the words will be displayed. Press any number to continue! \n");
scanf("%d",&p);

for(i = 0; i<2; i++)
for(ii=0;ii<2;ii++)
printf("Word > %s:\n",words[i][ii]);

//words[1][1]="Nice";

printf("ENTER A NUMBER[#] TO EXIT: >> ");
scanf("%d",&p);
===============================================

Lets say that further down this program I would like to replace the last
word "Human" to "Nice". Why wouldn't I be able to do it with the following
line:

words[1][1]="Nice";

Because arrays are _not_assignable_. You can still do it using 'memcpy'
or 'strcpy':

strcpy(words[1][1], "Nice");

Anyhow, if I try this, it gives the following error:

c:\_DTS_PROGRAMMING\c\GREEN_OSBOURN_P177_PointersWithArrays\P177.cpp(108) :

The extension of the file ('.cpp') suggest that you're using C++. Why do
you then claim that you're using 'C'? And if you are, in fact, using C++,
then you should not really be using arrays of char, but instead use the
standard 'string' class...

error C2440: '=' : cannot convert from 'const char [5]' to 'char [10]'

The error seems to not be able to convert a 'const char' (Nice) to a char
(as array defined).

Not to a char. To an array of char.

So is it that when we declare an array this way:

char words[][2][10] =
{
"We", "Are",
"All", "Human"
};

then we cannot modify its contents anymore? Lets say we wnat to modify the
contents, what do we do?

We assign them, element by element, or use other means, like standard
library functions.

[..]

V
--
Please remove capital As from my address when replying by mail
Sorry, I do not respond to top-posted replies, please don't ask

.

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