Re: Variable array size allocation

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C++ ok, C fail..... ><!!

Compiling...
test.c
\test.c(10) : error C2065: 'new' : undeclared identifier
\test.c(10) : warning C4047: 'initializing' : 'char *' differs in levels of
indirection from 'int '
\test.c(10) : error C2143: syntax error : missing ';' before 'type'
\test.c(10) : error C2143: syntax error : missing ';' before '['
\test.c(10) : warning C4091: ' ' : ignored on left of 'char ' when no
variable is declared
Error executing cl.exe.


"Nishant Sivakumar" <nish@xxxxxxxxxxxxxxxxxxxxxxx> ¼¶¼g©ó¶l¥ó·s»D:Oqbo1ntWFHA.2684@xxxxxxxxxxxxxxxxxxxxxxx
> Something like :-
>
> char* pData = new char[size];
>
> Note that you cannot do :- char Data[size]
>
> --
> Regards,
> Nish [VC++ MVP]
> http://www.voidnish.com
> http://blog.voidnish.com
>
>
> "boki" <bokiteam@xxxxxxxxxxxxxx> wrote in message
> news:OeRB88rWFHA.3864@xxxxxxxxxxxxxxxxxxxxxxx
>> Hi All,
>>
>> I need to declare variable array size.
>>
>> I will receive data, but I can't sure the data length.
>>
>> I need a array to save it.
>>
>> Best regards,
>> Boki.
>>
>>
>
>


.

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