Re: char array and pointer?

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From: muchan (usenet_at_usenet.usenet)
Date: 08/13/04 

Date: Fri, 13 Aug 2004 11:56:48 +0200

Rola wrote:

> Hi Tomek,
>
> thank you for your advice, anyway this returns not only one char but all the
> chars from a given pos to the end of array. Am I doing something wrong?
>
> Rola
>
> "TomekG" <tomgas@cntk.pl> wrote in message
> news:O%23saCURgEHA.140@TK2MSFTNGP12.phx.gbl...
>
>>int pos;
>>*(array+pos) => value array[pos]
>>

Probably you missed the presence of '*'.

Here (array+pos) is a pointer to a character, that hold the address.
It may be used as holder of the address, which starts the string,
(that is terminated with char '\0' )

*(array+pos) is the content of the address, pointed by that pointer.
It is one char.

To clear the basic confusion, you should read an introductory text
about C and C++'s pointer, array, and general concept of "address".

muchan

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