Re: Problem when executing application from batch file
- From: "Someone" <nobody@xxxxxxx>
- Date: Tue, 4 Oct 2005 21:40:37 -0400
It appears that outside a batch file, i.e., in Command Prompt, the app is
started and you are returned to the "C:\" prompt immediately. In a batch
file it waits for the App to finish before going to the next line, so
checking for previous instance is not necessary. If you are at Command
Prompt and wanted to type the EXE name and wait till the program finishes,
use:
start /wait yourapp /para1 /para2...
"DanS" <t.h.i.s.n.t.h.a.t@xxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:Xns96E5DB32A2E19idispcom@xxxxxxxxxxxxxxxxx
> "Jack" <replyto@newsgroup> wrote in
> news:evhDSZUyFHA.464@xxxxxxxxxxxxxxxxxxxx:
>
>> I do not understand and maybe someone please can explain to why, after
>> executing the first line of the batch file the batch execution stops
>> until I close my application.
>> What kind of mechanism is that?
>> sample of batch file:
>> [].exe /5553331234
>> [].exe /5556770808
>> [].exe /5553451234
>>
>> That happens only if there is not previous instance running.
>> I can see batch execution in CMD window. I can see the first batch
>> line being executed and then nothing. I close my app and then second
>> line of batch file appears and my app is alive again. I close my app
>> and then the third line of batch file will appear.
>> If I understand the mechanism of that behaviour maybe I can patch over
>> that problem
>> Jack
>>
>
> Is that 3 seperate lines in the batch file ?
>
> In the OP, I thought by accept multiple command line params I thought you
> meant like: program.exe /param1 /param2 /param3
>
> The batch file acts exactly as it was intended. It runs the first line,
> waits until that program ends, then runs the next line.
>
> I would have written the command$ handler to parse the string and look for
> multiple params, which is what I thought you did, and you wouldn't have
> had
> this issue.
>
> Regards,
>
> DanS
>
.
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