Re: Splash Screen and Image Control Problem

Hi -- I know I'm a bit dense and I understand what you did... I just don't
understand how I fix this in my situation.

I just tried running the program on both a 96DPI and 120DPI screen. Here is
what the Height/Width properties are:

DPI96 (small fonts):
Height =4965
Width = 6510
ScaleHeight = 4965
ScaleWidth = 6510

DPI120 (large fonts):
Height = 4968
Width = 6504
ScaleHeight = 4968
ScaleWidth = 6504

Now, I tried using your code, and I'm not sure what or where to use the
results. I would think I have to somehow adjust the frmSplash properties to
new width/height values or perhaps the scaling. I'm not sure if I need to
replace with new values or add to what I already have.

Any help or further explanation would be greatly appreciated.




"Randy Birch" <rgb_removethis@xxxxxxxx> wrote in message
news:Onls1cHTFHA.2096@xxxxxxxxxxxxxxxxxxxxxxx
> The dell machine is using large fonts; you're using small fonts. A twip is
> a
> twip and has nothing to do with resolution. If the image you load is, say,
> 300x400 pixels, then it will be 300x400 pixels regarless as to the screen
> size, resolution or font size. What will change is the size of the pixel,
> so
> 300 pixels looks "smaller" on a 96 DPI screen than on a 120 DPI screen.
> But
> the measurement itself does not change.
>
> That said, you do have to account for the fact a form hard-coded to a
> specific size, stretching an image control to it's client area, may cause
> the image to stretch or appear off-centre (depending on the settings on
> the
> image control). That is what you have to account for, and you can
> determine
> the DPI prior to loading your form by a simple api call:
> http://vbnet.mvps.org/code/screen/screenfont.htm. If the result is 96 use
> your normal values. If the result is <> 96, then divide the result by 96
> to
> get the "scaling factor", and multiply the width and height by that factor
> to get the required area.
>
>
> Private Sub Command1_Click()
>
> Dim dpi As Long
> Dim factor As Single
>
> Dim defWidth As Long
> Dim defHeight As Long
>
> defWidth = 300
> defHeight = 400
>
> 'dpi = <result of API call>
> dpi = 96 'assume it returns 96
> factor = dpi / 96
>
> Debug.Print factor, defWidth * factor, defHeight * factor
>
>
> dpi = 120 'assume it returns 120
> factor = dpi / 96
>
> Debug.Print factor, defWidth * factor, defHeight * factor
>
> End Sub
>
> output:
>
> 1 300 400
> 1.25 375 500
>
>
> --
>
> Randy Birch
> MS MVP Visual Basic
> http://vbnet.mvps.org/
> ----------------------------------------------------------------------------
> Read. Decide. Sign the petition to Microsoft.
> http://classicvb.org/petition/
> ----------------------------------------------------------------------------
>
>
>
> "dm4714" <spam@xxxxxxxx> wrote in message
> news:uCHlvIHTFHA.3308@xxxxxxxxxxxxxxxxxxxxxxx
> :I have a VB6 form that starts up in middle of screen. The scale mode is
> "1
> : twip" and the scale height is 4965 and scale width is 6510. The height
> of
> : the form is 4965 and the width is 6510.
> :
> : I also have an image control overlaying the entire form. It's height is
> 4965
> : and width is 6510.
> :
> : The image displays fine on my PC and any PC that is using a 96 DPI size
> : font.
> :
> : On some laptops with wide screens, it would appear that Dell sets the
> font
> : to 120 DPI.
> :
> : The problem is, my form is not larger than my image, and looks very
> tacky
> : when it appears. Again, on a normal desktop with a 96 DPI font, the
> form
> : and image are exactly the same size.
> :
> : How do I adjust my form with/height to account for the difference in DPI
> : without having to adjust or stretch my image?
> :
> : Any sample code or explanations would be appreciated.
> :
> :
> :
>


.

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