Re: Regular Expression Question

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As does:
<script type='text/javascript'>
document.write("aaa1234567b45454bb".
replace(/.*?(\d)(?=(\d{3}))|.+$/g, "$1$2,").replace(/,+$/,""))
</script>

The second replace merely gets rid of trailing commas.

The first replace, doing the heavy lifting, says: eat chars
until there's a digit (that's the (\d), which we'll call $1)
followed by three other digits (which we'll call $2). When
that happens, replace $1 (and the prior characters) with:
$1 followed by $2 followed by ","

Characters now continue to be eaten starting from the char
following the $1 (in the original string). The eating does
not start from after the $2 because $2 was embedded within
a forward lookahead, namely the (?=...), so that the $2
chars did not get eaten in the prior part. Finally,
that |.+$ is there because once we get to the last set of 4
contiguous digits, we want to replace the remainder of the
string with the empty string (or more precisely, a comma),
so those final characters have to get eaten somehow (and
the plus ensures there is at least one character to eat).

This is a slight adaptation from the last part
of my Nov. 19 post in this same thread:
http://groups.google.com/group/microsoft.public.scripting.vbscript/browse_frm/thread/82238d66a934a547

Csaba Gabor from Vienna
.

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