Re: the "having" clause

From: Roji. P. Thomas (lazydragon_at_nowhere.com)
Date: 03/08/04


Date: Mon, 8 Mar 2004 15:54:17 +0530

Here is the original post from CELKO.
-------

Here is how
a SELECT works in SQL ... at least in theory. Real products will
optimize things when they can.

 a) Start in the FROM clause and build a working table from all of the
joins, unions, intersections, and whatever other table constructors are
there. The table expression> AS <correlation name> option allows you
give a name to this working table which you then have to use for the
rest of the containing query.

 b) Go to the WHERE clause and remove rows that do not pass criteria;
that is, that do not test to TRUE (reject UNKNOWN and FALSE). The WHERE
clause is applied to the working set in the FROM clause.

 c) Go to the optional GROUP BY clause, make groups and reduce each
group to a single row, replacing the original working table with the new
grouped table. The rows of a grouped table must be group
characteristics: (1) a grouping column (2) a statistic about the group
(i.e. aggregate functions) (3) a function or (4) an expression made up
those three items.

 d) Go to the optional HAVING clause and apply it against the grouped
working table; if there was no GROUP BY clause, treat the entire table
as one group.

 e) Go to the SELECT clause and construct the expressions in the list.
This means that the scalar subqueries, function calls and expressions in
the SELECT are done after all the other clauses are done. The "AS"
operator can also give names to expressions in the SELECT list. These
new names come into existence all at once, but after the WHERE clause,
GROUP BY clause and HAVING clause has been executed; you cannot use them
in the SELECT list or the WHERE clause for that reason.

If there is a SELECT DISTINCT, then redundant duplicate rows are
removed. For purposes of defining a duplicate row, NULLs are treated as
matching (just like in the GROUP BY).

 f) Nested query expressions follow the usual scoping rules you would
expect from a block structured language like C, Pascal, Algol, etc.
Namely, the innermost queries can reference columns and tables in the
queries in which they are contained.

As you can see, things happen "all at once" in SQL, not from left to
right as they would in a sequential file/proceudral language model. In
those languages, these two statements produce different results:
  READ (a, b, c) FROM File_X;
  READ (c, a, b) FROM File_X;

while these two statements return the same data:

SELECT a, b, c FROM Table_X;
SELECT c, a, b FROM Table_X;

Think about what a confused mess this statement is in the SQL model.

SELECT f(c2) AS c1, f(c1) AS c2 FROM Foobar;

That is why such non-sense is illegal syntax.

hint: Start using the AS operator for column and table aliases instead
of the proprietary overloaded equal sign. It will make your code more
readable and portable.

-- 
Roji. P. Thomas
SQL Server Programmer
"Amy" <XXXNOSPAMXXX___l.a@usa.com> wrote in message
news:eMMIpZPBEHA.2404@TK2MSFTNGP11.phx.gbl...
> Hi toylet,
>
> Logically, The SELECT list is processed after the GROUP BY clause and the
> HAVING filter.
> So, When SQL Server processes the HAVING clause, the column alias is not
yet
> 'known'.
> The only place you can use column aliases you define in the select list is
> in the ORDER BY clause which is processed last.
> This is not a SQL Server 'freak behaviour', it is by design and supports
the
> ANSI rules for query processing order.
> Search this forum for an article by Celko called 'Select Sequence' in
which
> he explains the whole thing very clearly.
> All you should do is change your query to:
>
> > select xx.pk, xx.amount, count(*) as recno
> > from tx xx, tx yy
> > where xx.pk>=yy.pk
> > group by xx.pk, xx.amount
> > having count(*) = 1
>
> HTH
>
> Amy
>
> "toylet" <toylet_at_mail.hongkong.com> wrote in message
> news:uHOOlNPBEHA.3472@TK2MSFTNGP09.phx.gbl...
> > Why did SQL Server complain about "invalid column recno" in the
> > following query? It worked in another database tool I am using.
> >
> > select xx.pk, xx.amount, count(*) as recno
> > from tx xx, tx yy
> > where xx.pk>=yy.pk
> > group by xx.pk, xx.amount
> > having recno = 1
> >
> > -- 
> >    .~.    Might, Courage, Vision. In Linux We Trust.
> >   / v \   http://www.linux-sxs.org
> > /( _ )\  Linux 2.4.22-xfs
> >    ^ ^    5:52pm up 2 days 2:02 load average: 0.99 0.97 0.96
>
>


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