Re: How to get exact matches & better ranked results using freetexttable?

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Its hard to tell from looking at your data what data belongs in what
columns, for example in this row

rank ref partno name
75 4126 145-UB BADGE, 7.00 X 7.00

is rank=75, ref=4126, partno=145-UB BADGE and name= 7.00 X 7.00

or is it something else like this
rank=75, ref=4126, partno=145-UB and name=BADGE, 7.00 X 7.00

Did you remove all of the letters and number from your noise word list?

Also perhaps you should just search on partno.

Also I think contains will give you what you are looking for, but its hard
to tell as I don't really understand what your data looks like.


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Hilary Cotter

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<jasolution@xxxxxxxxx> wrote in message
news:1168698214.665262.131510@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
I have a SQL Server 2000 table with a varchar column (these are part
numbers) that contains data like this:

145
145-SC
145-AB
145-2
145-8

The full text catalog also includes columns that hold part name and
part description. I'm using the following query to return results for
product searches:

select ftt.RANK,
products.ref,
products.partno,
products.partname,
products.refparent
from PRODUCTS
INNER JOIN
FREETEXTTABLE(products,*,'145-8') as ftt
ON
ftt.[KEY]=products.ref
order by ftt.rank desc

My results are:

rank ref partno name
278 3854 14 Aqua kit
278 3855 14-SCD Aqua kit
278 3856 14-SCZ Aqua kit
278 3857 14-UG Aqua kit
183 3868 19 Standard T&L Kit
183 3869 19-SCD Standard T&L Kit
183 3870 19-SCZ Standard T&L Kit
183 3871 19-UB Standard T&L Kit
75 4121 145 BADGE, 7.00 X 7.00
75 4122 145-8 BADGE, 7.00 X 7.00
75 4123 145-25 BADGE, 7.00 X 7.00
75 4124 145-SCD BADGE, 7.00 X 7.00
75 4125 145-SCZ BADGE, 7.00 X 7.00
75 4126 145-UB BADGE, 7.00 X 7.00

How can I improve my query to return 145-8 (in this instance) as the
highest ranking result?

Thanks for your help!



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