Re: internet connector email routing question

Change the existing SMTP Connector and add Mail02 as a local bridgehead. At
any point thereafter you may remove Mail01 as a local bridgehead; perhaps a
good time for that would be after you've moved off the last mailbox.
Seriously, there's no reason for you to do it the way you're asking except
to unduly complicate matters.
--
Ed Crowley MVP
"There are seldom good technological solutions to behavioral problems."
..

"Patrick" <Patrick@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:2A712213-7905-4D4D-92D3-DDC6836386E7@xxxxxxxxxxxxxxxx
Ed Crowley, thanks for your help.

Why I am asking this question?
Because I'm going to remove mail01 from exchange site, I want to create a
smtp connector for mail02 and confirmed users mailbox on mail02 can send
out
internet mail via mail02 smtp connector, then I can move mailbox from
mail01
to mail02.

How can i achive this?

Thanks for your help

Patrick



"Ed Crowley [MVP]" wrote:

An SMTP Connector is nothing more than a routing object. There's no
service
associated with the SMTP Connector. What you should have is one SMTP
Connector with both servers listed as local bridgeheads. Mail would not
route from Mail01 to Mail02 and then out to the Internet in that case.
--
Ed Crowley MVP
"There are seldom good technological solutions to behavioral problems."
..

"Patrick" <Patrick@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:3352775E-900A-4995-9C77-E14DE9368AA0@xxxxxxxxxxxxxxxx
Thanks for your help

I have 2 exchange 2k3 server (mail01, mail02) and user mailbox are
allocate
to these two exchange server equally.

If I create 2 smtp connectors: the first one use mail01 as bridgehead
server
and the 2nd one use mail02 as bridgehead server, with same address
space
"*"
and cost "1".

If user mailbox on "Mail01" and he send a internet email, which smtp
connector this mail will use?

If user mailbox on "Mail02" and he send a internet email, which smtp
connector this mail will use?

Can I configure it user on "Mail01" use Mail01's smtp connector?

Thanks for your help

Patrick












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