Re: Exchange 2003 Address Lists
- From: JvB <JvB@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Wed, 29 Aug 2007 12:56:00 -0700
Fern,
Make sure you change the memberof= value to the (full) distinguishedName of
the group you want to use, this includes the container (OU=) and domain
componenents (DC=).
In this example the domain name is MyDomain.Corp and the group "MyGroupName"
is in the "SomeOU" org. unit.
(&(mailNickName=*)(memberOf=CN=MyGroupName,OU=SomeOU,DC=MyDomain,DC=Corp))
You can view/copy the dist.name of the group if you use ADSiEdit.msc find
the group, select properties and select the field "distinguishedName". Copy
the name, but make VERY sure you don't change anything there. (adsiedit gives
you direct, uncontrolled access to the AD database).
Keep in mind that if you move or rename the group, you will need to change
the query too.
Regards,
Jeroen
"fern" wrote:
.
"JvB" <JvB@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:5FBC1A37-B724-4168-B901-E681603FE371@xxxxxxxxxxxxxxxx
Hi Fern,
You can add an addresslist in systemmanager and select a custom filter. On
the advanced tab you can add a custom LDAP query like this :
(&(mailNickName=*)(memberOf=CN=MyGroupName,OU=SomeOU,DC=MyDomain,DC=Corp))
thanks Jeroen, I'm sure if I just get the syntax right Ill get the results
im looking for.
Unfortunetly I have not been successful with the above.
Im trying to have all members of the global security group "g_helpdesk" get
outputed.
Thanks again.
Regards,
Jeroen
"fern" wrote:
As we speak users simply click "to:" and select the Global address list
and
then find their target and select. I would like to have something
similiar
yet instead of one large list have lets say 10 individual lists grouped
by
department name for example. I believe the solution is within Exchange
System manager and creating an address list. Yet I cant seem to create a
list with a filter simply displaying users who are a member of lets a
global
security group. Manually creating a group by hand selecting users seems
to
have also stumped me. There is probably a very simple solution and would
appreciate any response .. thanks.
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