Re: removing value within a string

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Hi there,
So sorry I was clearer... for problem #w, she had asked if there was a way
to use =RIGHT and the LEN function.

Since that morning note, she actually tried:
=LEFT(C5,LEN(C5)-16) and it produced the same results. She wanted to know if
this is a flexible enough solution to use in teh same way we used your
solution below.
take care, Jane

"T. Valko" wrote:

She was going to approach the problem with =RIGHT
but include LEN.. she wanted me to ask you if that
might also work?

To do what exactly?

Biff

"Jane" <Jane@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:0E256AE7-2EDD-4B70-B5C8-206E97787808@xxxxxxxxxxxxxxxx
Hi Biff,
I shared your solutions with a co-worker who also had a similar situation.
She was going to approach the problem with =RIGHT but include LEN.. she
wanted me to ask you if that might also work?
thank you, Jane

"T. Valko" wrote:

You're welcome. Thanks for the feedback!

Biff

"Jane" <Jane@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:BFABF616-1AB4-4351-A4B6-5403A81D73B3@xxxxxxxxxxxxxxxx
that was so clear - thank you so much for the explanation!
take care, Jane

"T. Valko" wrote:

Ooops! Correction needed:

In that case all we need to do is find the location of the opening
parenthesis "(" in the string and extract everything to the right of
that.

Should be:

In that case all we need to do is find the location
of the opening parenthesis "(" in the string and extract
everything to the LEFT of that.

Biff

"T. Valko" <biffinpitt@xxxxxxxxxxx> wrote in message
news:%23XcIEwjVHHA.480@xxxxxxxxxxxxxxxxxxxxxxx
=SUBSTITUTE(A1,RIGHT(A1,3),RIGHT(A1,2))+0

This formula is simply replacing the 3 characters from the right
with
the
2 characters from the right. If:

A1 = 66014

Replace 3 characters from the right = 014
With 2 characters from the right = 14

Result = 6614

The result of the Substitute function is always a TEXT value. The +0
coerces the result to be NUMERIC.

The second formula:

=LEFT(A1,FIND("(",A1)-2)

I'm assuming that the portion of the string that you want to extract
is
variable in length and that this portion is always present: (S)

TRAD EC JEANS (S) | CL11941033

In that case all we need to do is find the location of the opening
parenthesis "(" in the string and extract everything to the right of
that.
In this example the "(" is the 15th character. So we subtract 2, one
for
the "(" and one for the space before the "(". That results in 13. So
the
formula is returning the first 13 characters starting from the left.

Biff

"Jane" <Jane@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:1CD9E380-5070-4671-9A6A-2F638800F6EF@xxxxxxxxxxxxxxxx
and sorry I didn't combine my questions but for the 2nd solution
also....
if
'from the right is need, why go with LEFT? and how does the -2 work
into
it?
I just want to be able to understand it so I can explain it to some
one
else
if asked and alter if needed for future use.

Thank you again! Jane

"T. Valko" wrote:

Try these:

1st problem:

=SUBSTITUTE(A1,RIGHT(A1,3),RIGHT(A1,2))+0

2nd problem:

=LEFT(A1,FIND("(",A1)-2)

Biff

"Jane" <Jane@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:035CD3B2-E8A2-4019-904A-5B55788B44E4@xxxxxxxxxxxxxxxx
I believe these problems have the same solution.

1st problem:
I would like to be able to remove the zero that is placed 3
digits
from
the
RIGHT. The values are:
66014
8004
8015

The values should look like:
6614
804
815

2nd problem in the same mproject:
I would like to be able to remove the values, text, and/ or
spaces
that
are
16 places from the RIGHT.
The entry is:
TRAD EC JEANS (S) | CL11941033

The entry should look like:
TRAD EC JEANS

thank you for your help! :)















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