Re: Count unique if text
- From: "Mike Fogleman" <mikefogleman@xxxxxxxxxxxxx>
- Date: Sat, 20 Jan 2007 16:57:12 -0500
OK, now I find that the formula results are 1 too many. I hand counted,
twice, and got 55 and the formula result is 56. Could that be coming from
the Frequency function? (The data array having 1 more element than the bin
array.)
Mike F
"Mike Fogleman" <mikefogleman@xxxxxxxxxxxxx> wrote in message
news:e7CEewNPHHA.1248@xxxxxxxxxxxxxxxxxxxxxxx
It's working now. Somehow I had 2 instances of Excel open and everything
was nuts.
Thanks for your efforts...
Mike F
"Mike Fogleman" <mikefogleman@xxxxxxxxxxxxx> wrote in message
news:%23fu93UNPHHA.1248@xxxxxxxxxxxxxxxxxxxxxxx
Oh, one more issue, and this is probably the kicker to your formula. All
the text are hyperlinks, so what is in the cell is the display value of
the hyperlink. it looks like this if the news reader will display
correctly.
P2-2
P2-2
P2-7
P1-3
P-HE
P2-7
0
P11-2
P12-8
P12-8
P12-1
P12-1
P11-3
Mike F
"Mike Fogleman" <mikefogleman@xxxxxxxxxxxxx> wrote in message
news:%23EFV2FNPHHA.2312@xxxxxxxxxxxxxxxxxxxxxxx
Thanks for the formula, but one problem. It works if there are no blank
cells in the range, but in my column there are many blank cells and the
formula gives 0 for answer. Is there some way around this?
Mike F
"T. Valko" <biffinpitt@xxxxxxxxxxx> wrote in message
news:Ocj9jSMPHHA.324@xxxxxxxxxxxxxxxxxxxxxxx
Try this:
Entered as an array using the key combination of CTRL,SHIFT,ENTER (not
just ENTER):
=SUM(N(FREQUENCY(IF(ISTEXT(B1:B13),MATCH(B1:B13,B1:B13,0)),MATCH(B1:B13,B1:B13,0))>0))
Biff
"Mike Fogleman" <mikefogleman@xxxxxxxxxxxxx> wrote in message
news:uNxLD9LPHHA.4368@xxxxxxxxxxxxxxxxxxxxxxx
Column B has a mix of text and numbers. I want to count unique text
values only.
The answer to the following list would be 8.
P2-2
P2-2
P2-7
P1-3
P-HE
P2-7
6
P11-2
P12-8
P12-8
P12-1
P12-1
P11-3
Mike F
.
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