Re: macro OK in Excel 2003 but NOT in Excel 2000

Your suggestion put the final resolution to another problem and really solved
my issue. Thanks
--
AncientLearner
....never to old to learn something new


"Peter T" wrote:

I don't see anything wrong in your code that would fail due to version.

However your code would fail if the active*** is not a work***, eg it's
a chart-*** or no visible ***. Just in case, it might be worth the two
changes to the commented line below -

With Sheets("sheet1")
' Set rngFrom = .Range(.Range("A1"), .Cells(Rows.Count, "A").End(xlUp))
Set rngFrom = .Range(.Range("A1"), .Cells(.Rows.Count, 1).End(xlUp))

Regards,
Peter T


"AncientLearner" <AncientLearner@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:F8E605CE-6D94-427C-BEA9-939709697350@xxxxxxxxxxxxxxxx
I can run to following code in Excel 2003 but when I run it in Excel 2000
I
get an error/debug at the line >> Set rngFrom = <<<

Should I declare different variables because of 2000 version?

****
Sub ADP_ExportExcel()
'transpose horizontal column output (multiCol) into single column
(vertical)
Dim rngFrom As Range
Dim rngTo As Range
Dim rng As Range
With Sheets("sheet1")
Set rngFrom = .Range(.Range("A1"), .Cells(Rows.Count, "A").End(xlUp))
<<
End With
Set rngTo = Sheets("sheet2").Range("A1")
For Each rng In rngFrom
rngTo.Value = rng.Value
rngTo.Offset(1, 0).Value = rng.Offset(0, 1).Value '2 columns
rngTo.Offset(2, 0).Value = rng.Offset(0, 2).Value '3 columns
rngTo.Offset(3, 0).Value = rng.Offset(0, 3).Value '4 columns
Set rngTo = rngTo.Offset(4, 0) 'number of rows per item
Next rng
End Sub

--
AncientLearner
...never to old to learn something new



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