Re: array question
- From: Charlie <Charlie@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Mon, 2 Jul 2007 13:52:01 -0700
I'm sure it is slower, but the OP seemed to be interested in simplicity not
speed. What's a few banano-seconds if the project is not compute intensive?
"RB Smissaert" wrote:
Not sure that is any faster and my guess is that it is slower..
VB(A) is slow with string concatenations, plus you may come across
a differing array element early in the loops so exit early.
Only some testing will tell for sure what the fastest method is.
RBS
"Charlie" <Charlie@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:9EA2E411-EAE8-4327-9DAD-1DBF7B4E57EF@xxxxxxxxxxxxxxxx
Try using Join to convert the arrays to strings (There's a Split function
too):
If Join(arr1) = Join(arr2) Then
. . .
End If
"RB Smissaert" wrote:
Not sure I get the way you make your arrays.
Can't you simply do:
With ws
arr1 = .Range(.Cells(3, 2), .Cells(5, lastrow))
arr2 = .Range(.Cells(3, 1), .Cells(5, lastrow - 1))
End With
As to comparing arrays. I don't think there is any other way than to loop
through
all the array elements, of course getting out the loops if you find a
difference.
The only refinement I can think of is loop in such a way that you are
most
likely
to get a non-matching element as early as possible.
RBS
"Gary Keramidas" <GKeramidasATmsn.com> wrote in message
news:e1g0ziMvHHA.736@xxxxxxxxxxxxxxxxxxxxxxx
if i create 2 arrays from a range, is there a way to compare the entire
array, instead of element by element?
For i = 2 To lastrow
arr1 = ws.Range("c" & i & ":E" & i)
arr2 = ws.Range("c" & i - 1 & ":E" & i - 1)
i want to know when arr1 = arr2.
right now i just use a loop to check the elements and if they all
match, i
continue on.
--
Gary
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