Re: Find last instance of character in text
- From: "T. Valko" <biffinpitt@xxxxxxxxxxx>
- Date: Mon, 27 Nov 2006 22:34:57 -0500
Oh, OK. It does that.
Biff
"JMB" <JMB@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:D2198C81-9B72-4800-AEBA-1B61B7492D94@xxxxxxxxxxxxxxxx
But it was only supposed to pick up the ":", the OP said he was already
familiar w/the text functions and just needed to find the last character
position.
Nice suggestion for a non-array solution.
"T. Valko" wrote:
You need to add 1. It picks up the ":".
=MID(A1,MAX((MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)=":")*(ROW(INDIRECT("1:"&LEN(A1)))))+1,7)
Another way: (normally entered)
=MID(A1,FIND("~",SUBSTITUTE(A1,":","~",LEN(A1)-LEN(SUBSTITUTE(A1,":",""))))+1,7)
Biff
"JMB" <JMB@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:22F2A1AC-5B02-40E8-A9A8-E0E95AAB71B4@xxxxxxxxxxxxxxxx
Just change the cell references from A1 to C6.
"KonaAl" wrote:
Thanks for the reply, JMB. Assuming the "1:" s/b ":1", I couldn't get
this
to work. I tried changing the A1 references to C6, for example, and
still
got a #REF! error. Both times I entered as an array.
Even after looking at the help files for ROW and INDIRECT, I can't
figure
this out. Your help is appreciated.
Allan
"JMB" wrote:
One way
=MAX((MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)=":")*(ROW(INDIRECT("1:"&LEN(A1)))))
entered using Cntrl+Shift+Enter or you will get 0 or 1.
"KonaAl" wrote:
Hi All,
I need to be able to return an account number (7 digits) from a
text
string.
The account number is preceded by a colon. I'm very familiar
with
find,
left, len, right functions, etc. My problem is the there can be
several
colons in the string and the position changes. For example:
Text 1
1000000 · Cash & Cash Equivalents:1010000 · Cash Accounts:1012000
·
IBT:1012600 · IBT Cash {WF}
Text 2
1000000 · Cash & Cash Equivalents:1010000 · Cash Accounts:1013000
·
IBT - B
of A
What I need is 1012600 from the first string and 1013000 from the
second.
I can't figure out how to obtain the position of the last colon in
the string.
TIA,
Allan
.
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