Re: Passing a constant by reference

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Bob Altman wrote:
I want to call a function that takes a void* argument and pass it the address of a constant. Is there a way to do this without explicitly defining the constant and then passing the address of the constant? In other words, what I *don't* want to do is this:

const int myInt = 5;
MyFunc(&myInt);

I want to do something more like this:

MyFunct(&(int)5);

A constant expression has no address; what you're asking for is meaningless. It's like asking where the number 5 is stored in the computer. It's not stored anywhere, it just *is*. Storage locations produce addresses, not constant values. Aren't you accidentally confusing this with a literal address, i.e.

MyFunc((void*) 5);

This will convert the integer 5 to a memory location and pass that as a pointer. This will then most likely produce an access violation upon access, since "5" is rarely a valid address, but if the "void*" is meant to merely hold a pointer-sized value rather than an actual pointer, this might have some meaning.

--
J.
http://symbolsprose.blogspot.com
.

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