Re: Splitting double into integers
- From: "Peter Oliphant" <poliphant@xxxxxxxxxxxxxxxx>
- Date: Tue, 22 Nov 2005 07:08:57 -0800
Well, first off, how are you going to deal with trailing zeros? Note that "2
and 34" is the same as "2 and 340". I'll assume you don't want trailing
zeros.
You say you can get it to where you've got "2 and .34". Ok, you're more than
half way there. You want to know the number of digits in the fractional
part, and then multiply it by 10 to that power. To get the number of digits
is easy:
int Digit_Count( double value )
{
return (value.ToString())->Length ;
}
Note this will include the decimal point, so subtract one from this. So, you
want to do this (using your example):
34 = .34 * pow( 10, Digit_Count( .34 ) - 1 ) ;
Now just use variables where the "34" and ".34" are...
[==P==]
"H.B." <HB@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:98806582-91E9-44B4-A88D-8909A3E742A9@xxxxxxxxxxxxxxxx
> Hi,
>
> How can I split Double into two integers like the following example :
>
> 2.34 -> 2 and 34 (I dont want the modf() result that gives 2 and 0.34)
>
> Hugo
.
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