Re: How to implement 'atoi' when radix=16 and number string is negati


"Tracey" <Tracey@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:2D5D3B7E-979C-4EC1-8EFA-D5CB5EB64158@xxxxxxxxxxxxxxxx
> I'm learning C++ and was stuck when writing code to convert a negative
> decimal number string to a hexdecimal number. For example, suppose the
> function interface is defined as:
>
> int atoi( const char*, size_t radix)
>
> One input string is "-1234" and radix is 16.
>
> How to get the correct hexdecimal integer? Can anyone help ? Thanks in
> advance!
>

Let's start by agreeing that all integers are stored in memory the same way.
There is no decimal vs. hexadecimal in memory. If what you want is the
hexadecimal representation of -1234, you can use this:

char hexOutput[20];

int res = atoi("1234");

itoa(res,hexOutput,16);

cout << endl << hexOutput << endl;




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