Re: Opposite of typeof /GetType()

Sorry, if I misunderstood your question.

public class Foo<T>
where T : new()
{
protected T bar()
{
return new T();
}
}
public class SuperFoo : Foo<SuperFoo>
{
//Class code
}

SuperFoo super = new Foo<SuperFoo>().bar();


"Ade" <madge@xxxxxxxxxxx> schreef in bericht
news:b0046e01-9c4e-4cba-8bb6-5eb02cf9dd16@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Whereas typeof gets a Type from a class, I need to get a class from a
Type so that I may create the type at runtime.

Imagine if you wil

class foo
{
public foo bar()
{
foo newFoo = new GetType();
// Some magic goes here
return newFoo;
}
}

What would be the syntactically-correct way to do this? I want to
create, from the base class, a new instance of whatever type the
instance of foo is. eg calling bar() on

class superfoo : foo

will give me something unboxable to a superfoo.


.

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