Re: enum base class

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Actually, members of the enumeration are declared so only one bit of 32-bit
unsigned int is set.

e.g.

public enum MyEnum1
{
enumValue1 = 0x00000001,
enumValue2 = 0x00000002,
enumValue3 = 0x00000004,
enumValue4 = 0x00000008,
enumValue5 = 0x00000010,
enumValue6 = 0x00000020,
}

Then I check all enumeration / their values the same way. I just have many
enumerations for code clarity?

Best regards,
Jure

"Doug Semler" <dougsemler@xxxxxxxxx> wrote in message
news:uXCQZUn7HHA.4584@xxxxxxxxxxxxxxxxxxxxxxx
"Jure Bogataj" <jure.bogataj@xxxxxxxxxxxx> wrote in message
news:eBDU1Wj7HHA.2752@xxxxxxxxxxxxxxxxxxxxxxx
Hi all!

I have two enumerations:

public enum MyEnum1
and
public enum MyEnum2

I want to create function that accepts parameter as member of either
enumeration. Is this at all possible?
Something like:
public void MyFunc(EnumBase myEnumValue)
{
}

Or is there some other way to accomplish this. Actually I have arround 10
enums and I don't want to create separate functions since the logic is
the same?
Maybe I can accomplish something through System.Enum?



You could cast all of the enums to int and declare the function with the
int parameter.

However, I question a design that requires 10 different enumerations
which, when cast, provide the same values for a particular functionality.
If you're not examining the bits but need to keep the type, you can always
pass it to your function as an object:

void myFunc(object o)
{
Console.WriteLine(Enum.Format(o.GetType(), o, "x"));
}
--
Doug Semler, MCPD
a.a. #705, BAAWA. EAC Guardian of the Horn of the IPU (pbuhh).
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.

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