Re: ListView in a UserControl
- From: "Laurent Navarro" <yop@xxxxxxx>
- Date: Fri, 11 Aug 2006 11:48:17 +0200
Thanks Claes !
It's working, there was no need to create a set() function, as you said
!!!
Thanks a lot
"Claes Bergefall" <louplou@xxxxxxxxxxxxx> a écrit dans le message de news:
OqkjJAKvGHA.1852@xxxxxxxxxxxxxxxxxxxxxxx
Remove the set() part. You don't need it
I think Nicholas assumed you were using 2.0 (the
ColumnHeaderCollectionEditor doesn't seem to exist in 1.1). Try with this
[MergableProperty(false), Localizable(true),
DesignerSerializationVisibility(DesignerSerializationVisibility.Content)]
public ListView.ColumnHeaderCollection MyColumns
{
get
{
return(this.myListView.Columns);
}
}
/claes
"Laurent Navarro" <yop@xxxxxxx> wrote in message
news:e5DVY8IvGHA.3264@xxxxxxxxxxxxxxxxxxxxxxx
Hi Nicholas !
Thanks for your answer. I tried what you said, and Visual Studio
returns me some error... I use Visual Studio 2003, prehaps this is the
point.
Anyway, I see my collection on the parameter window of the designer
and when I click on it I have a wizard which helps me to create new
columns. As far as I don't close the designer, I can see my columns on my
form painted on Visual Studio. But when I launch my application or
close/reopen the designer, I have lost all my columns.
I guess the set() part of my parameter is wrong, but I don't know what
to do...
Thanks again ! :)
"Nicholas Paldino [.NET/C# MVP]" <mvp@xxxxxxxxxxxxxxxxxxxxxxxxxxx> a
écrit dans le message de news: uYcg5aIvGHA.1284@xxxxxxxxxxxxxxxxxxxxxxx
Laurent,
Two things first. One, your property should be public, otherwise, I
don't know how the designer is going to be able to access it.
Two, when you make it public, you will want to name it MyColumns, as
per the public naming convention.
That being said, you need to attach the following attributes to your
MyColumns property:
[MergableProperty(false), Localizable(true),
DesignerSerializationVisibility(DesignerSerializationVisibility.Content),
Editor("System.Windows.Forms.Design.ColumnHeaderCollectionEditor,
System.Design, Version=2.0.0.0, Culture=neutral,
PublicKeyToken=b03f5f7f11d50a3a", typeof(UITypeEditor)),
SRDescription("ListViewColumnsDescr")]
This will enable the property window to help with designing your
columns.
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mvp@xxxxxxxxxxxxxxxxxxxxxxxxxxx
"Laurent Navarro" <yop@xxxxxxx> wrote in message
news:uMve5TIvGHA.4160@xxxxxxxxxxxxxxxxxxxxxxx
Hello,
I'm creating a control including a listview. I would like to be able
to set the columns through the Design Tool in Visual Studio, so I
created a parameter to access the columns of my listview:
private ListView.ColumnHeaderCollection myColumns
{
get
{
return(this.myListView.Columns);
}
set
{
this.myListView.Columns.Clear();
foreach(ColumnsHeader column in value)
{
this.myListView.Columns.add(column);
}
}
Of course this is not working, I can insert my columns in the
designer, but when I launch my application, the collection is empty.
I'm sure what I did is dirty, but I don't know what to do... If someone
has a clue...
Thank !
Laurent
.
- References:
- ListView in a UserControl
- From: Laurent Navarro
- Re: ListView in a UserControl
- From: Nicholas Paldino [.NET/C# MVP]
- Re: ListView in a UserControl
- From: Laurent Navarro
- Re: ListView in a UserControl
- From: Claes Bergefall
- ListView in a UserControl
- Prev by Date: Re: Object oriented method is inefficient with database calling
- Next by Date: Re: DataRepeater/Continous Forms in C#
- Previous by thread: Re: ListView in a UserControl
- Next by thread: Re: ListView in a UserControl
- Index(es):
Relevant Pages
|
Loading
