Re: Implementing an interface with qualified templates

Dave,

Why not just declare the interface as generic?

public class Animal
{}

public class Fish : Animal
{}

public interface IZoo<T> where T : Animal
{
List<T> Animals { get; }
void Feed(T a);
}

public Aquarium : IZoo<Fish>
{

}

Hope this helps.


--
- Nicholas Paldino [.NET/C# MVP]
- mvp@xxxxxxxxxxxxxxxxxxxxxxxxxxx

"Dave Booker" <dbooksta@xxxxxxxxxxxxxxxx> wrote in message
news:0C1D6E11-3CF6-489A-B5A2-56A4518C53DF@xxxxxxxxxxxxxxxx
I want to do something like this:

public class Animal;

public interface IZoo
{
List<Animal> Animals { get; }
void Feed(Animal a);
}

public Aquarium<FISH> : IZoo where FISH : Animal
{
public List<FISH> Animals { get ...;}
public void Feed(FISH a) {...}
}

It seems like this should be possible, because FISH are guaranteed to be
Animals. I can dodge the generic collection problem by substituting an
ArrayList for the List<>, but I don't see why I have to. And then there's
the problem of the function argument.

Is there any way to implement a (non-templated) interface with a qualified
template, like what I'm suggesting here?


.

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