Re: ^ operator in VB.Net what in C#?

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Thanks, Dan ! I really should have written that test, haven't done any maths
in my applications for some time...

Regards - Octavio

"Dan Neely" <DanNeely@xxxxxxxxxxxxxxxxxxxxxxxxx> escribió en el mensaje
news:C236D252-CDB9-4A07-9B69-25104CC7DB4C@xxxxxxxxxxxxxxxx
>
>
> "Octavio Hernandez" wrote:
>> The Math.Pow() method accepts any double operands, so I guess it works by
>> means of logarithms, etc. which could be slower if the operands are
>> integers. That's what I meant.
>
> Or both of you could stop pontificating and write a testapp. :)
>
> Using releasemode code the breakeven point for math.Pow was ~30^30.
> Smaller pairs were much faster in a for loop, higher ones really showed
> the
> benefit of using logs instead of loops.


.



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