Re: File Transfer
- From: "Ignacio Machin \( .NET/ C# MVP \)" <ignacio.machin AT dot.state.fl.us>
- Date: Wed, 25 May 2005 08:34:57 -0400
Hi,
Basically what you want is a Send file / Receive file set of methods right?
IF so find below the code for those, I also include two help methods (
Read/WriteStringToNetwork ) that they use.
Also notice the small buffers cause these are meant to run on a PocketPC
Cheers,
--
Ignacio Machin,
ignacio.machin AT dot.state.fl.us
Florida Department Of Transportation
//************************************************************************
public void SendFile( string filename )
{
try
{
int readed=0;
byte[] buff = new Byte[2048];
FileStream fstream = new FileStream( filename, FileMode.Open);
//send the file length
WriteStringToNetwork( fstream.Length.ToString() );
//writer.WriteLine( fstream.Length);
//writer.Flush();
while( (readed=fstream.Read( buff, 0, 2048))>0 )
networkstream.Write( buff, 0, readed);
fstream.Close();
}
catch(Exception e)
{
throw new Exception("\n==>Method: NetAccess.SendFile, sending this file
:"+ filename +" :" + e.Message );
}
}
public void ReceiveFile( string filename)
{
try
{
int size= Convert.ToInt32(ReadStringFromNetwork());
FileStream fs = new FileStream( filename, FileMode.Create);
byte[] buff = new Byte[ size>40048?40048:size];
int readed=0;
int readedt=0;
int toread= size>40048?40048:size;
while( (readedt=networkstream.Read( buff, 0, toread))>0)
{
readed+= readedt;
fs.Write( buff, 0, readedt);
toread=(size-readed)>40048?40048:size-readed;
if ( toread == 0 ) break;
}
fs.Close();
}
catch(Exception e)
{
throw new Exception("\n==>Method: NetAccess.ReceiveFile, receiving this
file :"+ filename +" :" + e.Message );
}
}
public void WriteStringToNetwork(string towrite)
{
try
{
//char[] chars = towrite.ToCharArray();
foreach( char c in towrite.ToCharArray())
networkstream.WriteByte( Convert.ToByte( c));
networkstream.WriteByte( 13);
networkstream.WriteByte( 10);
//Now we have to convert the chars to byte
//writer.WriteLine( towrite);
//writer.Flush();
}
catch(Exception e)
{
throw new Exception("\n==>Method: NetAccess.WriteStringToNetwork,
writing this string " + towrite+ " :" + e.Message );
}
}
public string ReadStringFromNetwork( )
{
StringBuilder buff;
try
{
buff = new StringBuilder( 20);
int ch;
while( (ch=networkstream.ReadByte())!= -1)
{
if (ch == 13) continue;
if ( ch==10) return buff.ToString();
buff.Append( Convert.ToChar( ch));
}
}
catch(Exception e)
{
throw new Exception("\n==>Method: NetAccess.ReadStringFromNetwork,
reading string :" + e.Message );
}
return buff.ToString();
}
//*************************************************************************
"lkr" <lkr@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:BB1C124E-DC5A-472A-874B-826EA00C45E5@xxxxxxxxxxxxxxxx
> hi
> i got one file transfer program using serialization which has a limitation
> that i can send only 8192 bytes(8KB). i want to send more than that wht
> can i
> do. how can i divide the file into mutiple segment and send the file and
> receive it. here is the program below
>
> public static void SendFileInfo()
> {
> // Get file type or extension
> fileDet.FILETYPE = fs.Name.Substring((int)fs.Name.Length - 3, 3);
>
> // Get file length (Future purpose)
> fileDet.FILESIZE = fs.Length;
>
> XmlSerializer fileSerializer = new XmlSerializer(typeof(FileDetails));
> MemoryStream stream = new MemoryStream();
>
> // Serialize object
> fileSerializer.Serialize(stream, fileDet);
> // Stream to byte
> stream.Position = 0;
> byte[] bytes = new byte[stream.Length];
> stream.Read(bytes, 0, Convert.ToInt32(stream.Length));
>
> Console.WriteLine("Sending file details...");
>
> // Send file details
> sender.Send(bytes, bytes.Length, endPoint);
> stream.Close();
> }
> and in the receiving end
>
> public static void ReceiveFile()
> {
> try
> {
> Console.WriteLine(
> "-----------*******Waiting to get File!!*******-----------");
> // Receive file
>
> receiveBytes = receivingUdpClient.Receive(ref RemoteIpEndPoint);
>
> // Convert and display data
> Console.WriteLine("----File received...Saving...");
>
> // Create temp file from received file extension
> fs = new FileStream("temp." + fileDet.FILETYPE, FileMode.Create,
> FileAccess.ReadWrite, FileShare.ReadWrite);
> fs.Write(receiveBytes, 0, receiveBytes.Length);
>
> Console.WriteLine("----File Saved...");
> Console.WriteLine("-------Opening file with associated program------");
>
> Process.Start(fs.Name); // Opens file with associated program
> }
> catch (Exception e)
> {
> Console.WriteLine(e.ToString ());
> }
> finally
> {
> //fs.Close();
> receivingUdpClient.Close();
> }
> }
> plz give solution for this
>
> thanks for advance
> lkr
.
- References:
- File Transfer
- From: lkr
- File Transfer
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