Re: Help with the, "this" initializer in a constructor.

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From: Player (guess_at_My.email.address.scum.com)
Date: 11/01/04 

Date: Mon, 1 Nov 2004 17:04:43 -0000

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Yeah great thanks Nick Malik..

I went through what you said, read some more then experimented a little..

I came out of it with the following code...

class A
{
      public A()
      {
            myMethod();
       }

       public virtual void stuff()
       {
            Console.WrteLine("A");
        }
} // end class A

class B : A
{
     public B() : base()
     {
     }

     public override void myMethod()
     {
         Console.WriteLine("B");
     }
} // end class B

Which DOES end up giving me the desired output, "B".

And I now understand why it's done like that, and why the base constructor
is always called, explicitly or not; But how you can override such
constructors and/or methods in order to achieve the desired goal :)

In the case above, it's still calling the base constructor, which is calling
the, "myMethod()" method, it's just that I am explicitly calling the base
constructor in my derived class, AND overriding the, "myMethod" in the
derived class, to get the desired result.

Thanks again to all - appreciated :)

Player

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