Re: Creating my on variable

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From: Richard Blewett [DevelopMentor] (richardb_at_NOSPAMdevelop.com)
Date: 11/10/04 

To: microsoft.public.dotnet.framework
Date: Wed, 10 Nov 2004 12:08:50 -0800

The

 var = new Roby();

 simply reinitializes the memory of var, it doesn't perform a new allocation.

 Regards

 Richard Blewett - DevelopMentor
 http://www.dotnetconsult.co.uk/weblog
 http://www.dotnetconsult.co.uk

   nntp://news.microsoft.com/microsoft.public.dotnet.framework/>

 Jon,
 
 Ok, I tried a simple application to test your arguments.
 I created a struct with a variable
 And declared two structes as that struct.
 The first with a value (=5) and second referent with the first one, so
 everything that happends in the same memory space will be changed in the
 second too.
 Now I execute NEW in the first one.
 Look what happend. The second still pointing to the same memory space
 and have the last value that we had set (=5).
 But the First one has 0 as value.
 "NEW" always create a new instance in memory. To class and structs.
 So, when I'm executing a new in the operator, I'm creating a new
 instance from my variable(struct) and send the reference to the called
 variable.
 Calling ( a = 1) with execute ( (Operator ... ) return new
 Roby.Integer(1) )
 
 Sample:
 
 namespace ConsoleApplication1
 {
 struct Roby
 {
 public int I;
 }
 
 class Program
 {
 static void Main( string[] args )
 {
 Roby Var;
 Var.I = 5;
 Roby Var2 = Var;
 
 Var = new Roby();
 
 System.Console.WriteLine( "VAR : {0}" , Var.I );
 System.Console.WriteLine( "VAR2 : {0}" , Var2.I );
 System.Console.Read();
 
 }
 }
 }

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