RE: Remove app from both device and desktop
From: Raj Kumar (RajKumar_at_discussions.microsoft.com)
Date: 08/13/04
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Date: Fri, 13 Aug 2004 08:31:02 -0700
Hi! Ilya,
Thank you for the responding. I did not have the "Uninstall"entry but after
I modified the INI file I did not see any entry in the registry like MSDN
specifies:
"String that identifies the application's Windows Uninstall registry key
name. This name must match the application's registered Windows Uninstall key
name, which is found in the HKLM\Software\Microsoft\Windows
\CurrentVersion\Uninstall registry key"
I did not see a any entry there for my app. I did find an entry at:
HKLM\Software\Microsoft\Windows CE Services\AppMgr\Apps\<appname>
I put the same <appname> in the "Uninstall" entry in the INI file. Am I
putting the right value for this entry? Is there anything else I should be
doing?
Thanks again for your time.
Regards,
Kumar
""Ilya Tumanov [MS]"" wrote:
> Do you have correct "Uninstall" entry in your INI file?
>
> Please see this for more details:
>
> http://msdn.microsoft.com/library/default.asp?url=/library/en-us/wcesetup/ht
> ml/_wcesdk_Creating_an_ini_File_for_the_Application_Manager.asp
>
> Best regards,
>
> Ilya
>
> This posting is provided "AS IS" with no warranties, and confers no rights.
> --------------------
> > Thread-Topic: Remove app from both device and desktop
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> > From: =?Utf-8?B?UmFqIEt1bWFy?= <RajKumar@discussions.microsoft.com>
> > Subject: Remove app from both device and desktop
> > Date: Thu, 12 Aug 2004 08:13:03 -0700
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> >
> > Hi!
> > I am still trying to understand how activesync does the install/uninstall
> > operations. After I install the app on the device and the desktop, I open
> up
> > Activesync and using Tools->Add/Remove programs, I click on the checkbox
> for
> > my app and then click on 'Remove'. 'Remove' is supposed to remove the app
> > from the device as well as the desktop but that is only removing the app
> from
> > the device. An entry still exists in the Desktop's Add/Remove programs
> list.
> >
> > What am I failing to understand here? Can anyone explain this?
> >
> > Thanks for your time.
> > Regards,
> > Kumar
> >
>
>
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