Re: "Must declare the scalar variable @Nickname"...
From: Jiggaz (anonymous_at_discussions.microsoft.com)
Date: 07/10/04
- Next message: mahsa: "Re: access to control in footer template"
- Previous message: DalePres: "Re: Toolbar button"
- In reply to: Scott G.: "Re: "Must declare the scalar variable @Nickname"..."
- Next in thread: Scott Simons: "RE: "Must declare the scalar variable @Nickname"..."
- Messages sorted by: [ date ] [ thread ]
Date: Sat, 10 Jul 2004 10:25:11 -0700
No, what's failing is the stored procedure : it doesn't
return me 1 when it adds the user. Always return me "-1"...
Why? If there is an user it has to return me -1 but when it
adds must not..
How can i return a value depending on the result of INSERT
which could be get, after, by asp.net and show a message to
the user if his account has or hasn't been created?
Thanks.
>-----Original Message-----
>
> I'm not exactly sure what you are asking; are you saying
that your sproc is always returning -1? If you think the
SELECT * FROM users... should be "failing" try to return a
count or debug the sproc. You could also run put some SQL
PRINT statements in you sproc and run it from QueryAnalyzer
if you need to troubleshoot.
>
>Scott
>
> "Jiggaz" <anonymous@discussions.microsoft.com> wrote in
message news:2a92101c465da$bbec7bd0$a301280a@phx.gbl...
> i have done that :
> ________________
> IF EXISTS (SELECT * FROM users WHERE nickname = @Nickname)
> BEGIN
> -- the user is there
> RETURN -1
> END
> ELSE BEGIN
> insert into users values (@Nickname , @Password ,
> @Email , @Date, @Name, @Lastname, @Sexe,
> @Titre, @Adress, @Birthday, @Phonetel, @Mobilephone,
> @Website, 50, '', '', '', '', @MailsAllowed)
> RETURN 1
> END
> ___________________
>
> But, always return me -1 but, it's good: if user is
> already in the table, sql doesn't add him and if not
> exists, add! But always return me in msg box -1?
> How to get if it hsn't been added to show a message : good
> or error if already in base?
>
> Thanks. Regards.
>
>
> >-----Original Message-----
> >You might have better luck with this question in the
> sqlserver groups (microsoft.public.sqlserver.programming).
> In the meantime, why not let Transact-SQL do some of the
> work for you
> >
> >IF EXISTS (SELECT * FROM users WHERE nickname = @Nickname)
> BEGIN
> > -- the user is there
> >END
> >ELSE BEGIN
> > -- the user is not there
> >END
> >
> >Scott
> > "Jiggaz" <anonymous@discussions.microsoft.com> wrote in
> message news:2a52b01c465a7$a1ef12c0$a301280a@phx.gbl...
> > Hi,
> >
> > Look my stored procedure :
> > __________________
> > ALTER PROCEDURE dbo.CreateAccount
> >
> > @Nickname varchar(30),
> > @Password varchar(15),
> > @Email varchar(50),
> > @Date datetime,
> > @Name varchar(50),
> > @Lastname varchar(50),
> > @Sexe varchar(2),
> > @Titre varchar(15),
> > @Adress varchar(255),
> > @Birthday varchar(50),
> > @Phonetel varchar(50),
> > @Mobilephone varchar(50),
> > @Website varchar(255),
> > @MailsAllowed varchar(2)
> >
> > AS
> >
> > DECLARE @insertstring nchar(4000)
> > DECLARE @checkforexistingrecord VARCHAR(60)
> > DECLARE @add VARCHAR(2000)
> > DECLARE @usernick VARCHAR(30)
> >
> > SET @usernick = @Nickname
> >
> > SET @insertstring = 'DECLARE @checkforexistingrecord
> > VARCHAR(60)
> > SELECT nickname FROM users WHERE nickname = '''
> > + @usernick + ''''
> > EXEC(@insertstring)
> > SELECT @checkforexistingrecord = @@ROWCOUNT
> > __________________
> >
> > Why i get this error?
> > I just want to verify if the username already exists..
> >
> > Thanks. Regards.
- Next message: mahsa: "Re: access to control in footer template"
- Previous message: DalePres: "Re: Toolbar button"
- In reply to: Scott G.: "Re: "Must declare the scalar variable @Nickname"..."
- Next in thread: Scott Simons: "RE: "Must declare the scalar variable @Nickname"..."
- Messages sorted by: [ date ] [ thread ]