Re: P2P API. Error grouping id's.
From: Igor_RU (anonymous_at_discussions.microsoft.com)
Date: 04/24/04
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Date: Sat, 24 Apr 2004 04:36:02 -0700
Yes. I have no direct internet connection available and all machines in same subnet behind the same router.
In creatind cloud i can not use "Global_" cloude and i have no default clouds, thus i must use LinkLocal.
In joining cloude in should use invitation - XML where i have the name of cloude of group. Thus, when i create
group on 1'st machine, how can i join this group from 2'd machine using invitation?
Or o neet to set existing cloud name (on 2'd machine) in invitation?
----- Geogy Samuel [MSFT] wrote: -----
The problem is that your machines do not have a global IPv6 address. One
option is to try to enumerate the clouds on the 2nd/3rd machine and use the
LinkLocal cloud from that enumeration to join the group. This will work only
if all the 3 machines are behind the same router.
Please let us know if that works.
Geogy
--
This posting is provided "AS IS" with no warranties, and confers no rights.
"Igor_RU" <igor@crystall.tl.ru> wrote in message
news:930FD734-E52C-49CB-B387-70156499EAA8@microsoft.com...
> I'm using P2P SDK for XP. The problem is in grouping several identities in
> group. I create 3 id's on different computers in LAN and try to join them
> into one group.
> First Id create group, 2'd and 3'd join group. In function PeerGroupCreate
> i must use field pwzCloud. On 1'st computer i have
> LinkLocal_{E54C850C-CDB9-47CF-85AD-0E15DA60C73C} cloud. When 2'd Id try to
> join this group, it have error - unknow cloud, because i have no this
> cloud on 2'd and 3'd computer. This mean, that i can not join group from
> different comp? ?!?!?! I can not use pwzCloud = NULL, because have an
> error - unknow cloud.
>> More over. If i try to join 2'd Id in same group on same computer,
> everything well except one thing. When i try to get info about group
> (number of members, ...) a have always 1 - one member?!?!?! And status of
> group for 2'd Id - 0 (unknown), for 1'st - well (listening). And i have no
> events from group.
>> May be somebody can help me
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