Re: Transparency in DX 9.0.

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If you "manually copy" the bitmap, don't you care about 3D
render states, that would even not effect "D3D-copy operations".

D3D9 (in contrast to DD8) isn't focused on surface-handling, but
on GPU rendering 3D. It obviously isn't meant to be used for "playing"
with a collection of surfaces, the few 2D-copy mechanism found in D3D
mainly serve the purpose of getting texture data into the 3D pipeline
(and vice versa).

So you want the image to be copied to a texture (nothing else would
really make sense in D3D)? Then either lock() the surface of the
texture, and really do the manual copy (modified to include the
color-key operation you demand), or, as an alternative, you
could load the bitmap as it is to a texture, and "copy" it to a
final destination RT-texture, by using a screen aligned quad
plus pixel shader.

Gruss

Jan Bruns



<jturner1990@xxxxxxxxxxx> schrieb im Newsbeitrag news:1174839498.444695.307570@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Hello,

I'm manually copying an 8-bit, palettized bitmap onto a small surface
(24x24).

The bitmap is a red ball shape on a black bakground. I do not want
the black background of the image to appear on my white front buffer/
surface.

I have set the following states to signify that black pixels are not
to be rendered:

g_pd3dDevice->SetRenderState(D3DRS_ALPHAREF, (DWORD)0x00000001);
g_pd3dDevice->SetRenderState(D3DRS_ALPHATESTENABLE, TRUE);
g_pd3dDevice->SetRenderState(D3DRS_ALPHAFUNC, D3DCMP_GREATEREQUAL);


** I do not want to use D3DXCreateTextureFromFileInMemoryEx or any of
the other D3DX-based functions.

The black background still appears. Why? How do you get simple
transparency (equivalent to the old-style ColorKey effect) in DX9?

Thanks,
J

.

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