RE: Setting a Different DataField for each Label2()
- From: Guillermo <Guillermo@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Wed, 31 Aug 2005 07:43:04 -0700
My own reply.
Sorry, I found the error. Some Elem names at the Database had a blank space
right after the last character. It was invisible, of course, unless I placed
the pointer on it. Works fine now.
"Guillermo" wrote:
> Dim FLDS(6) As String
> Dim Elem As Integer
> [I load FLDS String Elements from DB, no problem]
>
> Private Sub Label1_Change(Index As Integer)
> For Elem = 1 To 6
> Label2(Elem).DataField = FLDS(Elem) [ I get Error 545 here]
> Next Elem
> [But if I set the DataField property MANUALLY, with the SAME String, it
> works fine.
> Why?. Thanks.Guillermo.]
.
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- From: Guillermo
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