Re: app.path in access 97 module
- From: "Brendan Reynolds" <brenreyn@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Sat, 16 Jul 2005 14:44:32 +0100
Not my idea, just something I picked up from the newsgroups.
In later versions of Access you can use CurrentProject.Path, but that was
new in Access 2000, so won't work in Access 97.
--
Brendan Reynolds (MVP)
"Chris" <Chris@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
news:792CEF9B-D377-4116-9AD0-976A07E312A9@xxxxxxxxxxxxxxxx
> Thanks
>
> Excellent approach.
>
> "Brendan Reynolds" wrote:
>
>> Left$(CurrentDb.Name, Len(CurrentDb.Name)-Len(Dir(CurrentDb.Name)))
>>
>> --
>> Brendan Reynolds (MVP)
>>
>>
>> "Chris" <Chris@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
>> news:A416F2CB-3C25-4911-AF18-86EEB525D5C9@xxxxxxxxxxxxxxxx
>> > Hi,
>> >
>> > In a VBA module in Access97 I want to call a shelled application.
>> >
>> > shell(app.path & "\myapp.exe")
>> >
>> > I can't seem to figure out which reference I will use to provide the
>> > app.path function to me. I get a library or function not found.
>> >
>> > or can I get the application path using application. in someway?
>> >
>> > thanks
>> >
>> > Chris
>> >
>>
>>
>>
.
- References:
- app.path in access 97 module
- From: Chris
- Re: app.path in access 97 module
- From: Brendan Reynolds
- Re: app.path in access 97 module
- From: Chris
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