Re: Checkbox
- From: "Chip1035" <Chip1035@xxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Wed, 6 Apr 2005 13:11:04 -0700
I have three tables, one table is employees with their extension, another
table with computer system configuration (serial #, OS, Office) another table
has the printers (serial #, make/model, ink). I have put together a form
that puts all three in one view. Form goes like this:
Employee Name and their extension, computer serial number of their computer
with a command button to open the computer form showing all the information,
and finally printer serial number with a command button opening the printer
form, showing all the information.
What I want to do is have a checkbox for the printer. If an employee has a
printer on their desk, I want to place a checkmark in the checkbox and have
the printer serial number show up. If the employee does NOT have a printer,
I want the checkbox unchecked and the printer serial number text box to be
hidden.
Right now, what it is doing is, if I place a checkmark for an employee who
has a printer, save the record, go to an employee record who does NOT have a
printer, the checkbox is checked and the printer serial number is visible but
blank. If I place a check in the checkbox, the printer serial number is
visible, it stays checked for all records with the printer serial visible, if
I uncheck, printer serial number hides, all records are unchecked with
printer serial # hidden.
"tina" wrote:
> > Record three has no printer, therefore, should
> > not have a checkmark and printer visable.
>
> maybe i have misunderstood what you're doing here. the code does nothing to
> add or delete a checkmark in the table's Yes/No field - it only acts to on
> what is there. you (or somebody) has to enter or remove a checkmark from
> each record, according to whether or not there is a printer associated with
> the record.
>
> the code in the form's OnCurrent event shows or hides the subform (i am
> assuming that PrinterSerial is the name of the subform control) in the
> current record based on whether or not there is a checkmark in the Yes/No
> field for that record. the same code in the checkbox control's AfterUpdate
> event shows or hides the subform based on the new value entered in the
> Yes/No field.
>
> > Should there be a "IF" statement/code?
>
> Me!PrinterSerial.Visible = Nz(Me!printchk = True, False)
>
> works exactly the same as
>
> If Nz(Me!printchk = True, False) = True Then
> Me!PrinterSerial.Visible = True
> Else
> Me!PrinterSerial.Visible = False
> End If
>
> use either one, to suit yourself.
>
> if you're doing something different than what i understood from your posts,
> please post a more detailed explanation of the table(s), the form/subform,
> and what you're trying to accomplish.
>
> hth
>
>
> "Chip1035" <Chip1035@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
> news:D2CA3AF1-6FB3-4B7C-AEB2-2A22227E812E@xxxxxxxxxxxxxxxx
> > I want to thank you for your help... I really appreciate it! Although,
> it
> > still is not working...
> >
> > The error has gone away, but the oriniginal problem persists. Record one
> > has no printer, no checkmark, no printer visable. Record two has a
> printer,
> > place a checkmark, printer is visable. Here is the problem... When I go
> back
> > to record one or go to record three, checkmark is present and printer is
> > visable, when it should not. Record three has no printer, therefore,
> should
> > not have a checkmark and printer visable.
> >
> > Should there be a "IF" statement/code?
> >
> > "tina" wrote:
> >
> > > try
> > >
> > > Me!PrinterSerial.Visible = Nz(Me!printchk = True, False)
> > >
> > > hth
> > >
> > >
> > > "Chip1035" <Chip1035@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
> > > news:41FA1C46-A6AB-4064-BB9A-6AA240DF1E2D@xxxxxxxxxxxxxxxx
> > > > Found it... Now, when I access the form, I get an error:
> > > >
> > > > Run-Time error '94'"
> > > > Invalid use of Null
> > > >
> > > > Click on Debug and it brings me to the Form_Current line with the code
> > > > highlighted. Here is my code
> > > >
> > > > PrinterSerial.Visible = Me!printchk = -1
> > > > ^---Is the name of textbox ^---Is the name of the checkbox
> > > > I want visable if checkbox is
> > > > checked, not if check box is
> > > > not checked
> > > >
> > > > If I click on End, tehn go fourth with checking the checkbox, no error
> > > comes
> > > > up but still does what I explained earlier.
> > > > "tina" wrote:
> > > >
> > > > > in design view, when you open the Properties box, make sure the
> > > Properties
> > > > > box's title bar says Form - not Section, or anything else. if it
> doesn't
> > > say
> > > > > Form, then double click in the gray square in the upper left corner
> of
> > > the
> > > > > design view window, at the junction of the vertical and horizontal
> > > rulers;
> > > > > that should change the Properties box title bar to Form. then click
> the
> > > > > Events tab and proceed as stated in my previous post.
> > > > >
> > > > > hth
> > > > >
> > > > >
> > > > > "Chip1035" <Chip1035@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
> > > > > news:AFE74F0D-EDA2-4528-8CB1-3030C541CF50@xxxxxxxxxxxxxxxx
> > > > > > I cannot locate OnCurrent event procedure. I am using Access
> 2000, am
> > > I
> > > > > > missing something, I feel like this is suppose to be right in
> front of
> > > me.
> > > > > > I right click on the an emtpy area in Design View, select
> Properties,
> > > > > cannot
> > > > > > see a OnCurrent.
> > > > > >
> > > > > > "tina" wrote:
> > > > > >
> > > > > > > in the table underlying the form, you should have a field to
> store
> > > the
> > > > > > > Yes/No value re printer availability. make sure that field is
> > > included
> > > > > in
> > > > > > > the form's RecordSource. bind the checkbox control to the Yes/No
> > > field
> > > > > (set
> > > > > > > the checkbox control's ControlSource to the name of the field).
> then
> > > > > include
> > > > > > > your code in the form's OnCurrent event procedure, and in the
> > > checkbox
> > > > > > > control's AfterUpdate event procedure. to add the code:
> > > > > > >
> > > > > > > 1. open the form in design view.
> > > > > > > 2. open the Properties box (if it's not already open), click on
> the
> > > > > Events
> > > > > > > tab, and then double click in the white space at the right of
> the On
> > > > > Current
> > > > > > > event (first event listed). Access will create the event
> procedure
> > > and
> > > > > open
> > > > > > > the VBA Editor window, with the cursor inside the procedure.
> > > > > > > 3. enter your line of code, as
> > > > > > >
> > > > > > > Private Sub Form_Current()
> > > > > > >
> > > > > > > PrinterControl.Visible = (Me!CheckBoxName = -1)
> > > > > > >
> > > > > > > End Sub
> > > > > > >
> > > > > > > 4. go back to form design view.
> > > > > > > 5. click on the checkbox control to select it.
> > > > > > > 6. in the Properties box, again double click on the AfterUpdate
> > > event
> > > > > line.
> > > > > > > 7. enter your code inside the procedure, same as before.
> > > > > > >
> > > > > > > hth
> > > > > > >
> > > > > > >
> > > > > > > "Chip1035" <Chip1035@xxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
> > > > > > > news:0594D03D-2A50-43DD-971F-85BF54CB86C5@xxxxxxxxxxxxxxxx
> > > > > > > > This is what I got
> > > > > > > > Inventory Form which shows employee name, extension, computer
> > > serial
> > > > > > > number
> > > > > > > > and a checkbox for printer. When the checkbox is checked, a
> > > subform
> > > > > shows
> > > > > > > > the printer's serial number.
> > > > > > > >
> > > > > > > > I have the following code as an AfterUpdate event
> > > > > > > > PrinterControl].Visible = Me![CheckBoxName] = -1
> > > > > > > >
> > > > > > > > Now, when I view a record and the checkbox is empty, the next
> > > record
> > > > > has
> > > > > > > the
> > > > > > > > checkbox empty, but if I want to place a checkbox to show that
> > > > > employee
> > > > > > > has a
> > > > > > > > printer, the previous record has the checkbox checked with the
> > > printer
> > > > > > > > subform empty. If I uncheck the record and go back to the one
> > > that
> > > > > should
> > > > > > > be
> > > > > > > > checked, I find the checkbox unchecked.
> > > > > > > >
> > > > > > > > It was suggested I enter the code above in the Form's current
> > > event.
> > > > > How
> > > > > > > > can I access the Form's current event, in order to place the
> code
> > > > > there?
> > > > > > > If
> > > > > > > > needed... If there is another code all together, bring it on
> so I
> > > > > could
> > > > > > > try
> > > > > > > > it. NOTE: I am not a pro at Access, rather just a
> beginner...
> > > Thank
> > > > > you
> > > > > > > > for any and all help, in advance...
> > > > > > > > --
> > > > > > > > -Chip
> > > > > > > > =)
> > > > > > >
> > > > > > >
> > > > > > >
> > > > >
> > > > >
> > > > >
> > >
> > >
> > >
>
>
>
.
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